[Sarkari-Naukri] time and work
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1. Work from Days:
| If A can do a piece of work in n days, then A's 1 day's work = | 1 | . |
| n |
2. Days from Work:
| If A's 1 day's work = | 1 | , | then A can finish the work in n days. |
| n |
3. Ratio:
If A is thrice as good a workman as B, then:
Ratio of work done by A and B = 3 : 1.
Ratio of times taken by A and B to finish a work = 1 : 3
Questions
| 1. A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in: | |||||||||||||||||||||
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2. A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in: | |||||||||||||||||||||
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3. P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work? | |||||||||||||||||||||
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| 4. A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in: | |||||||||||||||||||||
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5. A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in: | |||||||||||||||||||||
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6. Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is: | |||||||||||||||||||||
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7. A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in: | |||||||||||||||||||||
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| 8. X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last? | |||||||||||||||||||||
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9. A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone? | |||||||||||||||||||||
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10. A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C? | |||||||||||||||||||||
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11. A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day? | |||||||||||||||||||||
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12. Twenty women can do a work in sixteen days. Sixteen men can complete the same work in fifteen days. What is the ratio between the capacity of a man and a woman? | |||||||||||||||||||||
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13. 10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? | |||||||||||||||||||||
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| 14. 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it? | |||||||||||||||||||||
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15. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: | |||||||||||||||||||||||||||||||||||||||||||
Answers: 1. Answer: Option B Explanation:
|
2. Answer: Option B
Explanation:
| Suppose A, B and C take x, | x | and | x | days respectively to finish the work. |
| 2 | 3 |
| Then, | | 1 | + | 2 | + | 3 | | = | 1 |
| x | x | x | 2 |
| | 6 | = | 1 |
| x | 2 |
x = 12.
So, B takes (12/2) = 6 days to finish the work.
3. Answer: Option A
Explanation:
P can complete the work in (12 x 8) hrs. = 96 hrs.
Q can complete the work in (8 x 10) hrs. = 80 hrs.
|
| 1 | and Q's 1 hour's work = | 1 | . |
| 96 | 80 |
| (P + Q)'s 1 hour's work = | | 1 | + | 1 | | = | 11 | . |
| 96 | 80 | 480 |
| So, both P and Q will finish the work in | | 480 | | hrs. |
| 11 |
|
| | 480 | x | 1 | | = | 60 | days = 5 | 5 | days. |
| 11 | 8 | 11 | 11 |
4. Answer: Option C
Explanation:
| (A + B)'s 1 day's work = | 1 |
| 10 |
| C's 1 day's work = | 1 |
| 50 |
| (A + B + C)'s 1 day's work = | | 1 | + | 1 | | = | 6 | = | 3 | . .... (i) |
| 10 | 50 | 50 | 25 |
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
| From (i) and (ii), we get: 2 x (A's 1 day's work) = | 3 |
| 25 |
|
| 3 | . |
| 50 |
|
| | 1 | - | 3 | | = | 2 | = | 1 | . |
| 10 | 50 | 50 | 25 |
So, B alone could do the work in 25 days.
5. Answer: Option B
Explanation:
Ratio of times taken by A and B = 1 : 3.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes | | 3 | x 60 | | = 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | | 1 | + | 1 | | = | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
|
| 45 | = 22 | 1 | days. |
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6. Answer: Option B
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
| 5 : 4 :: 20 : x | | 4 x 20 | |
5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
7. Answer: Option C
Explanation:
(B + C)'s 1 day's work = | | 1 | + | 1 | | = | 7 | . |
| 9 | 12 | 36 |
| Work done by B and C in 3 days = | | 7 | x 3 | | = | 7 | . |
| 36 | 12 |
| Remaining work = | | 1 - | 7 | | = | 5 | . |
| 12 | 12 |
| Now, | 1 | work is done by A in 1 day. |
| 24 |
| So, | 5 | work is done by A in | | 24 x | 5 | | = 10 days. |
|
|
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8. Answer: Option B
Explanation:
| Work done by X in 4 days = | | 1 | x 4 | | = | 1 | . |
| 20 | 5 |
| Remaining work = | | 1 - | 1 | | = | 4 | . |
| 5 | 5 |
| (X + Y)'s 1 day's work = | | 1 | + | 1 | | = | 8 | = | 2 | . |
| 20 | 12 | 60 | 15 |
| Now, | 2 | work is done by X and Y in 1 day. |
| 15 |
| So, | 4 | work will be done by X and Y in | | 15 | x | 4 | | = 6 days. |
| 5 | 2 | 5 |
Hence, total time taken = (6 + 4) days = 10 days
9. Answer: Option C
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
|
| 1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
10. Answer: Option B
Explanation:
| C's 1 day's work = | 1 | - | | 1 | + | 1 | | = | 1 | - | 7 | = | 1 | . |
| 3 | 6 | 8 | 3 | 24 | 24 |
| A's wages : B's wages : C's wages = | 1 | : | 1 | : | 1 | = 4 : 3 : 1. |
| 6 | 8 | 24 |
|
| | 3 x | 1 | x 3200 | | = Rs. 400. |
| 24 |
11. Answer: Option B
Explanation:
| A's 2 day's work = | | 1 | x 2 | | = | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | | 1 | + | 1 | + | 1 | | = | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | | 1 | + | 1 | | = | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
12. Answer: Option B
Explanation:
(20 x 16) women can complete the work in 1 day.
| 1 | . |
| 320 |
(16 x 15) men can complete the work in 1 day.
|
| 1 |
| 240 |
| So, required ratio = | 1 | : | 1 | = 4 : 3. |
|
|
|
13. Answer: Option C
Explanation:
| 1 woman's 1 day's work = | 1 |
| 70 |
| 1 child's 1 day's work = | 1 |
| 140 |
| (5 women + 10 children)'s day's work = | | 5 | + | 10 | | = | | 1 | + | 1 | | = | 1 |
| 70 | 140 | 14 | 14 | 7 |
5 women and 10 children will complete the work in 7 days.
14. Answer: Option B
Explanation:
Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
| Then, 4x + 6y = | 1 | and 3x + 7y = | 1 | . |
| 8 | 10 |
| Solving the two equations, we get: x = | 11 | , y = | 1 |
| 400 | 400 |
|
| 1 | . |
| 400 |
|
| | 1 | x 10 | | = | 1 | . |
| 400 | 40 |
Hence, 10 women will complete the work in 40 days.
15. Answer: Option A
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
| 10 | 2 |
| Solving these two equations, we get : x = | 1 | and y = | 1 | . |
| 100 | 200 |
| (15 men + 20 boy)'s 1 day's work = | | 15 | + | 20 | | = | 1 | . |
| 100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Regards,
Samiullah Maniyar...
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